Steel Pan Posted July 18, 2010 Share Posted July 18, 2010 I have the basic design figured out, can anyone give me the ratio of the size of thewater inlet line to the suction line size? Also pressure/gpm needed to be effective?I've got a 40' drop and going from 3" to 1 1/2" line size to run my "Simple Simon".I'm hoping to run a 2" suction nozzle/power jet. :hmmmmm: Any tips will be greatly appreciated. :wubu: Quote Link to comment Share on other sites More sharing options...
El Dorado Posted July 18, 2010 Share Posted July 18, 2010 I have the basic design figured out, can anyone give me the ratio of the size of thewater inlet line to the suction line size? Also pressure/gpm needed to be effective?I've got a 40' drop and going from 3" to 1 1/2" line size to run my "Simple Simon".I'm hoping to run a 2" suction nozzle/power jet. :hmmmmm: Any tips will be greatly appreciated. :wubu:You will find your answer at this forum: GoldDredger.com unless Hoser provides an answer here...... Quote Link to comment Share on other sites More sharing options...
Steel Pan Posted July 18, 2010 Author Share Posted July 18, 2010 Thanks Steve,Here's what I gleaned from that site."Formula:The area of the jet in sq. inchs times 7% = eductor bore in sq. inchesExample: 2 inch jet [Pi x (Radius of jet - Squared) = jet in sq in.]2 inch jet = 3.14 x (1" (radius of jet) Squared)3.14 x (1 x 1) = 3.14 sq in for a 2" jet3.14 sq inches x 7% (.07) = .219 sq. Inch for eductorNow for the tricky part: convert backwards and finally come up with a bore diameter.Eductor size is .219 sq. In which we will call .22 - because it is easier. Divide .22 by 3.14(Pi) = .07 , now find square root of ..07 which by calculator is .264 IMPORTANT: this is the radius of the eductor size - NOT the bore size!Multiply .264 x 2 = .528". Refer to a conversion chart to find conversion of decimal inched to "regular" inches which is fractionally larger than 1/2".At 30 psi the 1/2' eductor will require 41 g.p.m. Without getting into an explanation of friction loss of your ten foot, one inch diameter pressure hose, you will require 33.5 psi at the pump to provide the 30 psi at the eductor."Thanks again! :wubu: Quote Link to comment Share on other sites More sharing options...
Steel Pan Posted July 18, 2010 Author Share Posted July 18, 2010 I broke a few down to the nearest 1/4 inch.Jet size / Educator bore1.5"--------- = .223 or 1/4" 2"----------- = .528 or 1/2" 2 1/2"------- = .661 or 3/4" 3"----------- = .793 or 3/4" 3.5 "-------- = .925 or 1" 4"----------- = 1.058 or 1" Quote Link to comment Share on other sites More sharing options...
Steel Pan Posted July 18, 2010 Author Share Posted July 18, 2010 Correct me if I'm wrong, but it seems to me that you need to develope a "spray" from the educator, inside the suction nozzle/power jet, in order to create a vacuum. A stream of water will just flow through the exhaust of the unit and not produce any vacuum at all.Right? :hmmmmm: Quote Link to comment Share on other sites More sharing options...
Steel Pan Posted April 16, 2014 Author Share Posted April 16, 2014 A little update,...There needs to be a "water column" in the hose for the pressure line to push.It is the "water column" moving toward the sluice that causes the vacuum. It is the location of the nozzle or jet in the line that determines the effect.Gotta have that push on the "water column" to get the suction you need. Quote Link to comment Share on other sites More sharing options...
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